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The formula used in this $$L(\mu H)=\frac{31.6*N^2*r1^2}{(6*r1+9*L+10*(r2-r1))}$$
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NOTEThis formula applies at ‘low’ frequencies (<3MHz) using
enameled copper wire tightly wound.
Please note that the diameter is measured from center of wire trough
center of the coil and to center of the wire on the opposite side.
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